# Navier - Stokes equation: Cylindrical coordinates ,, :

To use Stokes’ Theorem, we need to think of a surface whose boundary is the given curve C. First, let’s try to understand Ca little better. We are given a parameterization ~r(t) of C. In this parameterization, x= cost, y= sint, and z= 8 cos 2t sint. So, we can see that x2 + y = 1 and z= 8 x2 y. 2016-07-12 Remark: Stokes’ Theorem implies that for any smooth ﬁeld F and any two surfaces S 1, S 2 having the same boundary curve C holds, ZZ S1 (∇× F) · n 1 dσ 1 = ZZ S2 (∇× F) · n 2 dσ 2. Example Verify Stokes’ Theorem for the ﬁeld F = hx2,2x,z2i on any half-ellipsoid S 2 = {(x,y,z) : x2 + y2 22 + z2 a2 = 1, z > 0}. Math 396.

Math 396. Stokes’ Theorem on Riemannian manifolds (or Div, Grad, Curl, and all that) \While manifolds and di erential forms and Stokes’ theorems have meaning outside euclidean space, classical vector analysis does not." Munkres, Analysis on Manifolds, p. 356, last line. (This is false. In many applications, "Stokes' theorem" is used to refer specifically to the classical Stokes' theorem, namely the case of Stokes' theorem for n = 3 n = 3, which equates an integral over a two-dimensional surface (embedded in \mathbb R^3 R3) with an integral over a one-dimensional boundary curve.

Applications. Fluid mechanics calculators.

## Matematisk ordbok för högskolan: engelsk-svensk, svensk-engelsk

Solution. We’ll use Stokes’ Theorem. To do this, we need to think of an oriented surface Swhose (oriented) boundary is C (that is, we need to think of a surface Sand orient it so that the given orientation of Cmatches). Then, Stokes’ Theorem says that Z C F~d~r= ZZ S curlF~dS~.